2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

  • question_answer
    The \[{{K}_{sp}}\]for \[Cr{{(OH)}_{3}}\]is \[1.6\times {{10}^{-}}^{30}.\]The molar solubiity of this compound in water is :     AIEEE  Solved  Paper (Held On 11 May  2011)

    A) \[4\sqrt{1.6\times {{10}^{-30}}}\]

    B) \[4\sqrt{1.6\times {{10}^{-30}}/17}\]

    C) \[1.6\times {{10}^{-30}}/27\]

    D) \[2\sqrt{1.6\times {{10}^{-30}}}\]

    Correct Answer: B

    Solution :

                                    \[Cr{{(OH)}_{3}}(s)\underset{S}{\mathop{C{{r}^{3+}}}}\,(aq.)+\underset{3S}{\mathop{3O{{H}^{-}}}}\,(aq.)\]                 \[27\,{{S}^{4}}={{k}_{sp}}\]                 \[S={{\left( \frac{{{K}_{sp}}}{27} \right)}^{1/4}}={{\left( \frac{1.6\times {{10}^{-30}}}{27} \right)}^{1/4}}\]               


You need to login to perform this action.
You will be redirected in 3 sec spinner