A) 171.2
B) 68.4
C) 34.2
D) 136.2
Correct Answer: B
Solution :
\[{{\pi }_{1}}={{\pi }_{2}}\] \[{{C}_{1}}={{C}_{2}}\] \[\frac{5/342}{0.1}=\frac{1/M}{0.1}\] \[\frac{5}{342}=\frac{1}{M}\]\[\Rightarrow \]\[M=\frac{342}{5}=68.4gm/mol\]You need to login to perform this action.
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