A) greater than 0.148 kJ
B) between 0.148 kJ and 0.028 kJ
C) less than 0.028 kJ
D) equal to 0.002 kJ
Correct Answer: D
Solution :
\[Q=\int_{{}}^{{}}{mcdT}\] \[=\int\limits_{20}^{4}{0.1\times 32\times }\left( \frac{{{T}^{3}}}{{{400}^{3}}} \right)dT\approx 0.002kJ.\]You need to login to perform this action.
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