A) \[4\sqrt{1.6\times {{10}^{-30}}}\]
B) \[4\sqrt{1.6\times {{10}^{-30}}/17}\]
C) \[1.6\times {{10}^{-30}}/27\]
D) \[2\sqrt{1.6\times {{10}^{-30}}}\]
Correct Answer: B
Solution :
\[Cr{{(OH)}_{3}}(s)\underset{S}{\mathop{C{{r}^{3+}}}}\,(aq.)+\underset{3S}{\mathop{3O{{H}^{-}}}}\,(aq.)\] \[27\,{{S}^{4}}={{k}_{sp}}\] \[S={{\left( \frac{{{K}_{sp}}}{27} \right)}^{1/4}}={{\left( \frac{1.6\times {{10}^{-30}}}{27} \right)}^{1/4}}\]You need to login to perform this action.
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