A) \[{{k}_{2}}={{k}_{1}}{{e}^{E{{a}_{1}}/RT}}\]
B) \[{{k}_{2}}={{k}_{1}}{{e}^{E{{a}_{2}}/RT}}\]
C) \[{{k}_{1}}-A{{k}_{2}}{{e}^{E{{a}_{1}}/RT}}\]
D) \[{{k}_{1}}-2{{k}_{2}}{{e}^{E{{a}_{2}}/RT}}\]
Correct Answer: C
Solution :
\[{{K}_{1}}={{A}_{1}}{{e}^{-E{{a}_{1}}/RT}}\] \[{{K}_{2}}={{A}_{2}}{{e}^{-E{{a}_{2}}/RT}}\] \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{{{A}_{1}}}{{{A}_{2}}}{{e}^{({{E}_{a}}_{2}\,\,\,{{E}_{a}}_{1})RT}}\] \[{{K}_{1}}={{K}_{2}}A\times {{e}^{{{E}_{{{a}_{1}}}}/RT}}\]You need to login to perform this action.
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