A) \[10.2\] eV
B) 0 eV
C) \[3.4\] eV
D) \[6.8\] eV
Correct Answer: C
Solution :
Energy required to remove an electron from nth orbit of H-atom is \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}\] Here, \[n=2\] Therefore, \[{{E}_{2}}=-\frac{13.6}{{{2}^{2}}}=-3.4\,V\]You need to login to perform this action.
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