question_answer

Bond angle of \[{{109}^{o}}28\]'is found in   AIEEE  Solved  Paper-2002

A) \[N{{H}_{3}}\]      

B)           \[{{H}_{2}}O\]      

C)           \[\overset{\oplus }{\mathop{C}}\,{{H}_{5}}\]       

D)           \[\overset{\oplus }{\mathop{N}}\,{{H}_{4}}\]

Correct Answer: D

Solution :

\[{{109}^{o}}28'\], it means pure regular tetrahedral. \[N{{H}_{3}}\,s{{p}^{3}}\] pyramidal \[{{H}_{2}}O\,\,s{{p}^{3}}\] bent \[CH_{5}^{+}\] \[NH_{4}^{+}\,s{{p}^{3}}\] tetrahedral