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JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    Tube A has both ends open while tube B has one end closed, otherwise they are identical. The ratio of fundamental frequency of tubes A and B is   AIEEE  Solved  Paper-2002

    A) \[1:2\]   

    B)                           \[1:4\]                                     

    C) \[2:1\]                     

    D)           \[4:1\]

    Correct Answer: C

    Solution :

    Let the tubes A and Shave equal length called as\[l\]. Since, tube A is opened at both the ends therefore its fundamental frequency                                 \[{{n}_{A}}=\frac{v}{2\,l}\]                          ... (i) Since, tube B is closed at one end, therefore its fundamental frequency                                 \[{{n}_{B}}=\frac{v}{4\,l}\]                           ?. (ii)              From Eqs. (i) and (ii), we get                                    \[\frac{{{n}_{A}}}{{{n}_{B}}}=\frac{v/2\,l}{v/4\,l}=\frac{4}{2}=2:1\]


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