A) 10
B) 20
C) \[25.5\]
D) 5
Correct Answer: B
Solution :
By applying the Bernoulli's theorem just inside and outside the hole. Take reference line for gravitational potential energy at the bottom of the vessel. Let \[{{p}_{0}}\] be the atmospheric pressure, \[\rho \] be the density of liquid and v be the velocity at which water is coming out. \[{{\rho }_{inside}}+\rho gh+0={{\rho }_{outside}}+\frac{\rho {{v}^{2}}}{2}\] \[\Rightarrow \] \[{{p}_{0}}+\rho gh={{p}_{0}}+\frac{\rho {{v}^{2}}}{2}\] \[\Rightarrow \] \[v=\sqrt{2gh}=\sqrt{2\times 10\times 20}=20\,m/s\]You need to login to perform this action.
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