A) g, g
B) g-a, g-a
C) g-a, g
D) a, g
Correct Answer: C
Solution :
The net force in any direction equal the product of mass and acceleration in the direction of net force. Also net force means the vector sum of forces acting on a body. Apparent weight of ball \[w'=w-R\] \[R=ma\] (acts upward) \[mg-R=ma\] \[w'=mg-ma=m(g-a)\] Hence, apparent acceleration in the lift is g ? a. Now, if the man is standing stationary on the ground, then the apparent acceleration of the falling ball is g.You need to login to perform this action.
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