A) \[M{{R}^{2}}/2\]
B) \[M{{R}^{2}}\]
C) \[2M{{R}^{2}}\]
D) \[M{{R}^{2}}/4\]
Correct Answer: A
Solution :
Moment of inertia of circular wire about its axis is \[M{{R}^{2}}\]. Consider two diameters \[XX'\] and \[YY'\] moment of inertia about any of this diameter is same let us say \[l\]. From perpendicular axis theorem, \[l+l=M{{R}^{2}}\] \[l=\frac{M{{R}^{2}}}{2}\]You need to login to perform this action.
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