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JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    Energy of H-atom in the ground state is -13.6 eV, hence energy in the second excited state is   AIEEE  Solved  Paper-2002

    A) \[-6.8\] eV             

    B)           \[-3.4\] eV             

    C)           \[-1.51\] eV          

    D)           \[-4.53\] Ev

    Correct Answer: C

    Solution :

    \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV\] For second excited state \[n=3\],                    \[{{E}_{3}}=-\frac{13.6}{9}=-1.51\,eV\]


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