A) \[x+2y\]
B) \[2x+y\]
C) \[y-x\]
D) \[y-2x\]
Correct Answer: C
Solution :
At LHS (oxidation) \[2\times (Ag\xrightarrow{{}}A{{g}^{+}}+{{e}^{-}})\]\[E_{ox}^{o}=-x\] At RHS (reduction) \[C{{u}^{2+}}2{{e}^{-}}\xrightarrow{{}}Cu\] \[E_{red}^{o}=+y\] \[2Ag+C{{u}^{2+}}\xrightarrow{{}}Cu+2A{{g}^{+}},E_{red}^{o}=(y-x)\] NOTE \[{{E}^{o}}\] values remain constant when half-cell equation is multipled/divided.You need to login to perform this action.
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