question_answer

Rate constant k of the first order reaction when initial concentration \[{{C}_{0}}\] and concentration \[{{C}_{t}}\] at time \[t\] is given by equation \[kt=\log \,{{C}_{0}}-\log {{C}_{t}}\] Graph is a straight line if we plot   AIEEE  Solved  Paper-2002

A) \[t\,\,vs\,\,\log \,\,{{C}_{0}}\]   

B)           \[t\,\,vs\,\,\log \,{{C}_{t}}\]          

C)           \[{{t}^{-1}}\,\,vs\,\,\log \,{{C}_{t}}\]       

D)           \[\log \,\,{{C}_{t}}\,vs\,\,\log \,\,{{C}_{t}}\]

Correct Answer: B

Solution :

\[K\,\,f=-\log {{C}_{0}}-\log {{C}_{t}}\] \[y=mx+C\] \[\log {{C}_{t}}=\frac{-K\,t}{2.303}+\log {{C}_{0}}\]