2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    A heat engine absorbs heat \[{{q}_{1}}\] from a source at temperature \[{{T}_{1}}\] and heat \[{{q}_{2}}\] from a source at temperature \[{{T}_{2}}\]. Work done is found to be \[J({{q}_{1}}+{{q}_{2}})\] This is in accordance with

    A) first law of thermodynamics

    B) second law of thermodynamics

    C) Joules equivalent law

    D) None of the above

    Correct Answer: C

    Solution :

    Joules law suggests \[J=\frac{\text{Mechanical work done by the system},\text{ w}}{\text{Net heat given to the system Q}}\] Hence. \[J=\frac{w}{{{q}_{1}}+{{q}_{2}}}\] Hence, \[w=J\,({{q}_{1}}+{{q}_{2}})\] is consent with Joules law of equivalence.


You need to login to perform this action.
You will be redirected in 3 sec spinner