A) \[16:25\]
B) \[9:1\]
C) \[4:5\]
D) \[5:4\]
Correct Answer: D
Solution :
Resolving power (RP) of an optical instrument is inversely proportional to \[\lambda \] i.e., RP \[\propto \frac{1}{\lambda }\]. \[\therefore \frac{\text{Resolving power at}\,{{\lambda }_{1}}}{\text{Resolving power at}\,{{\lambda }_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{5000}{4000}=5:4\]You need to login to perform this action.
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