A) \[{{0.186}^{o}}\]
B) \[{{0.0.512}^{o}}\]
C) \[{{186}^{o}}\]
D) \[{{5.12}^{o}}\]
Correct Answer: B
Solution :
\[\Delta {{T}_{b}}=m{{K}_{b}}\] \[\Delta {{T}_{f}}=m\,{{K}_{f}}\] \[\frac{\Delta {{T}_{b}}}{\Delta {{T}_{f}}}=\frac{{{K}_{b}}}{{{K}_{f}}}=\frac{0512}{1.86}\] \[\Delta {{T}_{b}}=\frac{0.512}{1.86}\times 0.186={{0.0512}^{o}}\]You need to login to perform this action.
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