JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    If \[\omega \] is an imaginary cube root of unity, then \[{{(1+\omega -{{\omega }^{2}})}^{7}}\] equals   AIEEE  Solved  Paper-2002

    A) \[128\,\omega \]                

    B)           \[-128\,\omega \]              

    C)           \[128\,{{\omega }^{2}}\]

    D)           \[-128\,{{\omega }^{2}}\]

    Correct Answer: D

    Solution :

    If \[\omega \] is a cube root of unity, then \[1+\omega +{{\omega }^{2}}=0\] and \[{{\omega }^{3}}=1\]. Now, \[{{(1+\omega -{{\omega }^{2}})}^{7}}={{(-{{\omega }^{2}}-{{\omega }^{2}})}^{7}}\]                                                    \[(\because 1+\omega +{{\omega }^{2}}=0)\]                    \[={{(-2{{\omega }^{2}})}^{7}}=-{{2}^{7}}.\,{{\omega }^{14}}\]                    \[=-128\,{{({{\omega }^{3}})}^{4}}{{\omega }^{2}}=-128\,{{\omega }^{2}}\]                                                    \[(\because {{\omega }^{3}}=1)\]


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