A) \[\log \,(x-1)\]
B) \[\log \,\,x\]
C) \[x\]
D) None of these
Correct Answer: C
Solution :
\[{{e}^{(x-1)-\frac{1}{2}{{(x-1)}^{2}}+\frac{1}{3}{{(x-1)}^{3}}-...}}\] \[={{e}^{\log (1+x-1)}}=x\]
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