A) 16 J
B) 8 J
C) 32 J
D) 24 J
Correct Answer: B
Solution :
The work is stored as the PE of the body and is given by \[U=\int_{{{x}_{1}}}^{{{x}_{2}}}{{{F}_{external}}dx}\] or \[U=\int_{{{x}_{1}}}^{{{x}_{2}}}{kx\,dx=\frac{1}{2}k({{x}_{2}}^{2}-{{x}_{1}}^{2})}\] \[(\therefore \left| F \right|=kx)\] \[=\frac{800}{2}[{{(0.15)}^{2}}-{{(0.05)}^{2}}]\] (\[\because k=800\], given) \[=400[0.2\times 0.1]=8\,J\]
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