A) \[9.2\]
B) \[7.8\]
C) 4
D) \[9.8\]
Correct Answer: B
Solution :
The system of masses is shown below. From the figure. For block A, \[F-{{T}_{1}}=\] ma ... (i) and for block B, \[{{T}_{1}}-{{T}_{2}}=\] ma ... (ii) Eq. (i) gives \[102-{{T}_{1}}\,=2\times 0.6\,\Rightarrow \,{{T}_{1}}=102-12=9N\] Again from Eq. (ii), we get \[9-{{T}_{2}}=2\times 0.6\] \[\Rightarrow \] \[{{T}_{2}}=9-1.2=7.8\,N\]You need to login to perform this action.
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