A) 10 units
B) 15 units
C) 5 units
D) None of these
Correct Answer: B
Solution :
Equation of circle is \[{{x}^{2}}+{{y}^{2}}-4x-2y-20=0\]. whose centre is C(2,1) and radius is 5 units. At point? (10,7), \[{{S}_{1}}={{10}^{2}}+{{7}^{2}}-4\times 10-2\times 7-20>0\] So, P lies outside the circle. Now, \[PC=\sqrt{{{(2-10)}^{2}}+{{(1-7)}^{2}}}\] \[=\sqrt{{{8}^{2}}+{{6}^{2}}}=\sqrt{{{10}^{2}}}=10\] \[\therefore \] Greatest distance between circle and the point \[p=10+5=15\] units.You need to login to perform this action.
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