A) \[{{\log }_{e}}x\]
B) \[x\]
C) \[{{\log }_{x}}e\]
D) None of these
Correct Answer: B
Solution :
\[\sum\limits_{n=0}^{\infty }{\frac{{{({{\log }_{e}}x)}^{n}}}{n!}=1+\frac{{{\log }_{e}}x}{1!}+\frac{{{({{\log }_{e}}x)}^{2}}}{2!}+...}\] \[={{e}^{{{\log }_{e}}x}}=x\]You need to login to perform this action.
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