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JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    If in a circular coil A of radius R, current j is flowing and in another coil B of radius 2 R, a current 2 i is flowing, then the ratio of the magnetic fields, \[{{B}_{A}}\] and \[{{B}_{B}}\] produced by them will be   AIEEE  Solved  Paper-2002

    A) 1

    B)                                           2                                

    C)           \[1/2\]                    

    D)           4

    Correct Answer: A

    Solution :

    Magnetic field in circular coil A is \[{{B}_{A}}=\frac{{{\mu }_{0}}\,Ni}{2\,R}\] where, R is radius and \[i\] is current flowing in coil.              Similarly,                 \[{{B}_{B}}=\frac{{{\mu }_{0}}N(2i)}{2.\,(2R)}=\frac{{{\mu }_{0}}Ni}{2R}\] \[\Rightarrow \]                   \[\frac{{{B}_{A}}}{{{B}_{B}}}=\frac{1}{1}=1\]


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