A) \[z\hat{i}-x\hat{k}\]
B) 0
C) \[y\,\hat{i}\]
D) \[-z\,\hat{i}+x\,\hat{k}\]
Correct Answer: A
Solution :
Given that, \[a=x\,\hat{i}+y\,\hat{j}+z\hat{k}\] and \[b=\hat{j}\] are such that a, c and b form a right handed system. \[\therefore \] \[c=b\times a=\left| \begin{matrix} {\hat{i}} & {\hat{j}} & {\hat{k}} \\ 0 & 1 & 0 \\ x & y & z \\ \end{matrix} \right|=z\,\hat{i}-x\hat{k}\]You need to login to perform this action.
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