A) \[y=0\]
B) \[y\le 2\]
C) \[y\ge -2\]
D) \[y\ge 2\]
Correct Answer: D
Solution :
Since, \[y={{\sin }^{2}}\theta +\cos e{{c}^{2}}\theta \] \[={{\sin }^{2}}\theta +\cos e{{c}^{2}}\theta -2+2\] \[={{(\sin \theta -\cos ec\theta )}^{2}}+2\] \[\left( \cos ec\theta =\frac{1}{\sin \theta } \right)\] \[\Rightarrow \] \[y\ge 2\]You need to login to perform this action.
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