A) \[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\]
B) \[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{2}}].2N{{H}_{3}}\]
C) \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl.\,N{{H}_{3}}\]
D) \[[Co{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{2}}.N{{H}_{3}}\]
Correct Answer: A
Solution :
\[Co{{(N{{H}_{3}})}_{5}}Cl]\,C{{l}_{2}}\underbrace{{{[Co{{[N{{H}_{3}})}_{5}}Cl]}^{2+}}+2C{{l}^{-}}}_{three\,\,\,ions}\] \[\underset{free}{\mathop{2C{{l}^{-}}}}\,\,\,+\,\,\,2A{{g}^{+}}\xrightarrow{{}}2AgCl\] 2 mot 2mol. 2 molYou need to login to perform this action.
You will be redirected in
3 sec