A) \[N{{a}^{+}},C{{a}^{2+}},M{{g}^{2+}}\]
B) \[{{N}^{3-}},{{F}^{-}},N{{a}^{+}}\]
C) Be, \[A{{l}^{3+}},C{{l}^{-}}\]
D) \[C{{a}^{2+}},C{{s}^{+}},Br\]
Correct Answer: B
Solution :
\[{{N}^{3-}}7+3=10\] electrons \[{{F}^{-}}9+1=10\] electrons \[N{{a}^{+}}11-1=10\] electronsYou need to login to perform this action.
You will be redirected in
3 sec