A) \[1\times {{10}^{-10}}\]
B) \[29.5\times {{10}^{-2}}\]
C) 10
D) \[1\times {{10}^{10}}\]
Correct Answer: D
Solution :
\[E_{cell}^{o}=\frac{2.303RT}{n\,F}\log \,{{K}_{eq}}\] \[0.295=\frac{0.0591}{2}\log \,{{K}_{eq}}\] \[\therefore \] \[\log \,{{K}_{eq}}=10\] \[\therefore \] \[{{K}_{eq}}={{10}^{10}}\]You need to login to perform this action.
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