A) \[4.0\] g
B) \[8.0\] g
C) \[12.0\] g
D) \[16.0\] g
Correct Answer: A
Solution :
\[C={{C}_{0}}{{\left( \frac{1}{2} \right)}^{y}}\] \[y=\frac{Total\text{ }time}{{{T}_{1/2}}}=\frac{18}{3}=6\] \[{{C}_{0}}=256\,g\] \[\therefore \] \[{{C}_{\left( undecayed \right)}}=256{{\left( \frac{1}{2} \right)}^{6}}=\frac{256}{64}=4\,g\]You need to login to perform this action.
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