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JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    The radionuclide \[_{90}^{234}Th\] undergoes two successive \[\beta \] -decays followed by one \[\alpha \] -decay. The atomic number and the mass number respectively of the resulting radionuclide are     AIEEE  Solved  Paper-2003  

    A)                         92 and 234    

    B)       94 and 230                          

    C)  90 and 230       

    D)       92 and 230

    Correct Answer: C

    Solution :

    \[_{90}^{234}Th\xrightarrow{-2\beta }_{92}^{234}X\xrightarrow{-\,\alpha }_{90}^{230}Y\]


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