A) \[[{{L}^{-1}}T]\]
B) \[[{{L}^{2}}{{T}^{2}}]\]
C) \[[{{L}^{2}}{{T}^{-2}}]\]
D) \[[L{{T}^{-1}}]\]
Correct Answer: C
Solution :
As we know that formula for velocity of EM-wave in a medium of permittivity \[{{E}_{0}}\] (i.e., free space) is \[v=\frac{1}{\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}}\] \[\therefore \] \[{{v}^{2}}=\frac{1}{{{\mu }_{0}}{{\varepsilon }_{0}}}={{[L{{T}^{-1}}]}^{2}}\] \[\therefore \] \[\frac{1}{{{\mu }_{0}}{{\varepsilon }_{0}}}=[{{L}^{2}}{{T}^{-2}}]\]
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