A) ethylamine salt and methanoic acid
B) propanoic acid and ammonium salt
C) ethanoic acid and ammonium salt
D) methylamine salt and ethanoic acid
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}NC+{{H}_{2}}O\xrightarrow{{{H}^{+}}}\underset{formic\,\,acid}{\mathop{HCOOH}}\,+{{C}_{2}}{{H}_{5}}N{{H}_{2}}\] \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}+{{H}^{+}}\xrightarrow{{}}\underset{salt}{\mathop{{{C}_{2}}{{H}_{5}}NH_{3}^{+}}}\,\]
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