A) \[C{{H}_{3}}-C{{H}_{2}}-COOH\]
B) \[C{{H}_{2}}=CH-C{{H}_{2}}OH\]
C) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]
D) \[C{{H}_{3}}-C{{H}_{2}}-CHO\]
Correct Answer: B
Solution :
\[LiAl{{H}_{4}}\] reduces ?COOH to ?\[C{{H}_{2}}OH\] without affecting C = C bond. \[C{{H}_{2}}=CH-COOH\xrightarrow[THF]{LiAl{{H}_{4}}}\]\[C{{H}_{2}}=CH-C{{H}_{2}}OH\]You need to login to perform this action.
You will be redirected in
3 sec