A) \[+250\] kJ
B) \[-250\] kJ
C) \[+125\] kJ
D) \[-125\] kJ
Correct Answer: D
Solution :
\[CH=C{{H}_{2}}+{{H}_{2}}\xrightarrow{{}}C{{H}_{3}}-C{{H}_{3}}\] \[\Delta H={{(BE)}_{reac\tan ts}}-{{(BE)}_{products}}\] \[=4{{(BE)}_{C-H}}+{{(BE)}_{C=C}}+{{(BE)}_{H-H}}\] \[-[6{{(BE)}_{C-H}}+{{(BE)}_{C-C}}]\] = - 125 kJYou need to login to perform this action.
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