A) \[-1\]
B) 0
C) \[+1\]
D) \[+2\]
Correct Answer: B
Solution :
\[{{K}_{4}}[Ni{{(CN)}_{4}}]\xrightarrow{{}}4{{K}^{+}}+{{[Ni{{(CN)}_{4}}]}^{4-}}\] \[x+(4\times -1)=-4\] \[x-4=-4\] x = 0You need to login to perform this action.
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