A) \[1.08\] g
B) \[10.8\] g
C) \[21.6\] g
D) 108 g
Correct Answer: B
Solution :
\[A{{g}^{+}}+{{e}^{-}}\xrightarrow{{}}Ag\] 9650C = 0.1 F = 0.1 equivalent Ag = 0.1 mol Ag = 10.8 g AgYou need to login to perform this action.
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