A) \[-{{0.480}^{o}}C\]
B) \[-{{0.360}^{o}}C\]
C) \[-{{0.260}^{o}}C\]
D) \[+\,{{0.480}^{o}}C\]
Correct Answer: A
Solution :
\[\Delta {{T}_{f}}=molality\,\times {{K}_{f}}\times i\] \[H\,X\,{{H}^{+}}+{{X}^{-1}}\] \[=0.2\times 1.85\times 1.3\] \[\alpha =0.3\] \[\therefore \,\,Fp=-{{0.481}^{\text{o}}}C\] \[i=1+\alpha =1.3\]You need to login to perform this action.
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