A) \[C{{F}_{4}},S{{F}_{4}}\]
B) \[Xe{{F}_{2}},C{{O}_{2}}\]
C) \[B{{r}_{3}},PC{{l}_{3}}\]
D) \[P{{F}_{5}},l{{F}_{5}}\]
Correct Answer: B
Solution :
In \[C{{O}_{2}}\], C-atom is sp-hybridised thus it has linear structure. In \[Xe{{F}_{2}},\,Xe\] is \[s{{p}^{3}}\]d hybridised with three lone-pairs of electrons on equatorial position. This minimizes repulsion hence it has also linear structure.You need to login to perform this action.
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