A) \[16\times {{10}^{-32}}\] J
B) \[3.1\times {{10}^{-26}}\] J
C) \[4\times {{10}^{-10}}\] J
D) \[32\times {{10}^{-32}}\] J
Correct Answer: D
Solution :
In this case, the work done is stored as electrostatic potential energy in the capacitor. \[W=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\frac{{{q}^{2}}}{C}\] \[=\frac{1}{2}\times \frac{{{(8\times {{10}^{-18}})}^{2}}}{100\times {{10}^{-6}}}\] \[=\frac{1}{2}\times \frac{64\times {{10}^{-36}}}{100\times {{10}^{-6}}}=32\times {{10}^{-32}}J\]
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