A) \[\frac{30\,E}{100.5}\]
B) \[\frac{30\,E}{100-05}\]
C) \[\frac{30\,(E-0.5i)}{100}\], where \[i\] is the current in the potentiometer wire
D) \[\frac{30\,E}{100}\]
Correct Answer: D
Solution :
Potential difference of wire \[V\propto l\] \[\therefore \] \[\frac{V}{E}=\frac{l}{L}\] where, \[l=\] length of balance point of potentiometer-wire L = length of potentiometer wire or \[V=\frac{l}{L}E\] \[V=\frac{30\times E}{100}=\frac{30}{100}E\]You need to login to perform this action.
You will be redirected in
3 sec