A) \[0.180\] g
B) \[0.141\] g
C) \[0.126\]g
D) \[0.242\] g
Correct Answer: C
Solution :
According to Faraday's law of electrolysis, m = Zit, \[\frac{{{m}_{Zn}}}{{{m}_{Cu}}}=\frac{{{Z}_{Zn}}}{{{Z}_{Cu}}}\] \[\therefore \] \[\frac{0.13}{{{m}_{Cu}}}=\frac{32.5}{31.5}\] \[{{m}_{Cu}}=0.126\,\,g\]You need to login to perform this action.
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