A) \[11%\]
B) \[21%\]
C) \[42%\]
D) \[10.5%\]
Correct Answer: D
Solution :
The time period of simple pendulum is given by \[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \] \[\frac{\Delta T}{T}=\frac{1}{2}\frac{\Delta \,l}{l}\] (differentiating) Given, \[\frac{\Delta \,l}{l}=\] 21% \[\therefore \] \[\frac{\Delta T}{T}=\frac{1}{2}\times 21%=10.5%\]You need to login to perform this action.
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