A) \[\sqrt{3}\] W
B) W
C) \[(\sqrt{3}/2)\]W
D) 2 W
Correct Answer: A
Solution :
As the work \[W=MB\,(1-\cos \theta )\] \[\Rightarrow \] \[W=MB\,(1-\cos \,{{60}^{o}})\] \[(\because \theta ={{60}^{o}})\] \[\Rightarrow \] \[W=\frac{MB}{2}\] \[\therefore \] MB = 2 W Torque, \[\tau =MB\sin {{60}^{o}}\] \[=\frac{MB\sqrt{3}}{2}=\frac{2W\sqrt{3}}{2}=W\sqrt{3}\]You need to login to perform this action.
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