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JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    A force\[F=(5\hat{i}+3\hat{j}+2\hat{k})\] is applied over a particle which displaces it from its origin to the point\[r=(2\hat{i}-\hat{j})m\]. The work done on the particle in joules is

    A) - 7           

    B)                        + 7                         

    C)        + 10                       

    D)        + 13

    Correct Answer: B

    Solution :

    Work done in displacing the particle \[W=F.r=(5\hat{i}+3\hat{j}+2\hat{k}).(2\hat{i}-\hat{j})\] \[=5\times 2+3\times (-1)+2\times 0=10-3=7\,J\]


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