A) 12 and 4
B) 12 and 5
C) 16 and 4
D) 16 and 5
Correct Answer: B
Solution :
Electronic configuration of\[Cr(Z=24)\]is\[n\] | \[l\] | |
\[1{{s}^{2}}\] | 1 | 0 |
\[2{{s}^{2}}\] | 2 | 0 |
\[2{{p}^{6}}\] | 2 | 1 |
\[3{{s}^{2}}\] | 3 | 0 |
\[3{{p}^{6}}\] | 3 | 1 |
\[3{{d}^{5}}\] | 3 | 2 |
\[4{{s}^{1}}\] | 4 | 0 |
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