question_answer

Amongst the following compounds, the optically active alkane having lowest molecular mass is

A) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}\]

B) \[C{{H}_{3}}-C{{H}_{2}}-\overset{\begin{smallmatrix}  C{{H}_{3}} \\  | \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\]

C) \[C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  {{C}_{2}}{{H}_{5}} \end{smallmatrix}}{\overset{\begin{smallmatrix}  H \\  | \end{smallmatrix}}{\mathop{C}}}\,-\]

D) \[C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\]

Correct Answer: C

Solution :

contains asymmetric carbon, thus optically active.