A) \[-5.2\]
B) \[-15.7\]
C) \[-24.8\]
D) \[-48.78\]
Correct Answer: D
Solution :
For a transistor amplifier in common emitter configuration, current gain \[{{A}_{i}}=-\frac{{{h}_{fe}}}{1+{{h}_{oe}}{{R}_{L}}}\] where,\[{{h}_{fe}},{{h}_{ce}}\]are hybrid parameters of a transistor. \[\therefore \]\[{{A}_{i}}=-\frac{50}{1+25\times {{10}^{-6}}\times 1\times {{10}^{3}}}=-48.78\]You need to login to perform this action.
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