A) \[Xe{{F}_{4}}\]
B) \[S{{F}_{4}}\]
C) \[BF_{4}^{-}\]
D) \[{{[Ni{{(CN)}_{4}}]}^{2-}}\]
Correct Answer: C
Solution :
Tetrahedral structure is associated with\[s{{p}^{3}}\] hybridised central atom without any lone pair. The structure of all the compounds given are as follows\[Xe{{F}_{4}}\] | Distorted octahedral | |
\[{{[Ni{{(CN)}_{4}}]}^{2-}}\] | Square planar | |
\[S{{F}_{4}}\] | Distorted trigonal bipyramidal | |
\[BF_{4}^{-}\] | Tetrahedral |
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