A) 0.001 M
B) 0.01 M
C) 0.02 M
D) 0.1 M
Correct Answer: B
Solution :
Avogadro's number\[{{N}_{A}}=6.02\times {{10}^{23}}=1\]mole \[\therefore \]\[6.02\times {{10}^{20}}\] molecules = 0.001 mole in 100 mL (0.1 L solution) \[\therefore \]Molar concentration\[=\frac{mol}{volume\,in\,L}\] \[=\frac{0.001}{0.1}\] \[=0.01\text{ }M\]You need to login to perform this action.
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